[最も好ましい] (x^2 y^2 – 1)^3 – x^2y^3 =0 209095-(x^2+y^2-1)^3-x^2y^3=0
Q Tbn And9gct3k0oj6k9nzsxbju4sknb0gj4bya Hzwwhxf3bzbpce6sp6gxof4si Usqp Cau The given equation is x 2y – 3 = 0 Assuming the values for any one variable, we can get the value for the other Thus, assuming the values of y as 2 and 2 we get y = 2⇒ x = 3 – 2(2) = 7 y = 2Now substituting value of y in equation 1 we get Now yushii Goswami Btech in Engineering & Electronics and instrumentationEngineering, RV College of Engineering (RVCE) (Graduated 22) (x^2+y^2-1)^3-x^2y^3=0